问题
填空题
若线段AB的两个端点A、B分别在x轴、y轴上滑动，|AB|=60，点M是AB上一点，且|AM|=36，则点M的轨迹方程是__________.
答案
+
=1
设A(x0,0)、B(0,y0)、M(x,y)，则x02+y02="3" 600,x0=
x,y0=
y.
∴
x2+
y2="3" 600,即+=1.
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若线段AB的两个端点A、B分别在x轴、y轴上滑动，|AB|=60，点M是AB上一点，且|AM|=36，则点M的轨迹方程是__________.
+=1
设A(x0,0)、B(0,y0)、M(x,y)，则x02+y02="3" 600,x0=x,y0=y.
∴x2+y2="3" 600,即+=1.
| 阅读理解。 | ||||
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