问题
填空题
已知实数x、y满足
|
答案
∵x、y满足
+y2+2y+1=0,x-1
∴
+(y+1)=0,x-1
∴x-1=0,y+1=0,
解得x=1,y=-1,
∴x2012-y2012=12012-(-1)2012
=1-(-1)
=2.
故答案为:2.
已知实数x、y满足
|
∵x、y满足
+y2+2y+1=0,x-1
∴
+(y+1)=0,x-1
∴x-1=0,y+1=0,
解得x=1,y=-1,
∴x2012-y2012=12012-(-1)2012
=1-(-1)
=2.
故答案为:2.