问题
选择题
设函数f(x)=
|
答案
设x＞0，则-x＜0，
∵f（x）是奇函数，
∴f（x）=-f（-x）=-[2×（-x）+1]=2x-1，
于是g（2）=f（2）=2×2-1=3．
故选A．
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设函数f(x)=
|
设x＞0，则-x＜0，
∵f（x）是奇函数，
∴f（x）=-f（-x）=-[2×（-x）+1]=2x-1，
于是g（2）=f（2）=2×2-1=3．
故选A．
| 用方框内所给词的适当形式填空。 | |
2. Students usually ________ learning English in primary schools. 3. They ________ a big party to celebrate (庆祝) the harvest last October. 4. Professor Li stopped ______ after he had a heart disease. 5. I ________ Lucy last night, but she was not at home. |