问题
单项选择题
设(1+ax)8=b0+b1x+b2x2+…+b8x8,若b3,b4,b5成等差数列,则a的值为()。
A.A
B.B
C.C
D.D
答案
参考答案:C
解析:
由已知,得
即
故2a2-5a+2=0,(2a-1)(a-2)=0
解得a=或a=2
故正确答案为C。
设(1+ax)8=b0+b1x+b2x2+…+b8x8,若b3,b4,b5成等差数列,则a的值为()。
A.A
B.B
C.C
D.D
参考答案:C
解析:
由已知,得
即
故2a2-5a+2=0,(2a-1)(a-2)=0
解得a=或a=2
故正确答案为C。
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