函数f(x)的导函数f'(x)的图像如图3-1所示，则在 (-∞，+∞)内f(x)的单调递增区间是( )．
A．(-∞，-1)
B．(-∞，0)
C．(0，1)
D．(-1，+∞)
参考答案：D
解析：
[分析]： 本题考查的知识点是根据一阶导数f'(x)的图像来确定函数曲线的单调区间． 因为在x轴上方f'(x)＞0，而f'(x)＞0的区间为f(x)的单调递增区间，所以选D
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