问题
解答题
(1)解不等式组
(2)化简(
|
答案
(1)由①得:x≥1;
由②得:x<3;
∴1≤x<3,
∴整数解为:1,2;
(2)原式=(
-2x x-1
)÷x x+1
,1 x2-1
=(
-2x x-1
)•(x+1)(x-1),x x+1
=2x(x+1)-x(x-1),
=2x2+2x-x2+x,
=x2+3x.
(1)解不等式组
(2)化简(
|
(1)由①得:x≥1;
由②得:x<3;
∴1≤x<3,
∴整数解为:1,2;
(2)原式=(
-2x x-1
)÷x x+1
,1 x2-1
=(
-2x x-1
)•(x+1)(x-1),x x+1
=2x(x+1)-x(x-1),
=2x2+2x-x2+x,
=x2+3x.