解方程:(1)(x﹣1)2=4
(2)x2﹣4x+1=0
(3)3x2+5(2x+1)=0
(4)3(x﹣5)2=2(5﹣x)
解:(1)直接开方得,x﹣1=±2,
解得x1=3,x2=﹣1;
(2)∵a=1,b=﹣4,c=1,△=b2﹣4ac=16﹣4=12
∴x=,解得x1=2+
,x2=2﹣
;
(3)去括号,得3x2+10x+5=0,
∵a=3,b=10,c=5,
△=b2﹣4ac=100﹣60=40
∴x=,
解得x1=,x2=
;
(4)移项,得3(x﹣5)2+2(x﹣5)=0,
提公因式,得(x﹣5)(3x﹣15+2)=0,
即x﹣5=0或3x﹣13=0,
解得=5,
=
.