问题
解答题
解方程:
(1)x2-4x-1=0(用配方法);
(2)2x2-7x=4.
答案
(1)x2-4x-1=0,
x2-4x+4=5,
(x-2)2=5,
x-2=±
,5
解得x1=2+
,x2=2-5
;5
(2)2x2-7x=4,
2x2-7x-4=0,
(2x+1)(x-4)=0,
解得x1=-
,x2=4.1 2
解方程:
(1)x2-4x-1=0(用配方法);
(2)2x2-7x=4.
(1)x2-4x-1=0,
x2-4x+4=5,
(x-2)2=5,
x-2=±
,5
解得x1=2+
,x2=2-5
;5
(2)2x2-7x=4,
2x2-7x-4=0,
(2x+1)(x-4)=0,
解得x1=-
,x2=4.1 2