问题
选择题
△ABC中,A=
|
答案
根据正弦定理
=BC sinA
,AC sinB
=BC sinA AB sin(120°-B)
∴AC=sinB
=2BC sinA
sinB,AB=sin(120°-B)3
=3cosB+BC sinA
sinB3
∴△ABC的周长为2
sinB+3cosB+3
sinB+3=6sin(B+3
)+3π 6
故选D.
△ABC中,A=
|
根据正弦定理
=BC sinA
,AC sinB
=BC sinA AB sin(120°-B)
∴AC=sinB
=2BC sinA
sinB,AB=sin(120°-B)3
=3cosB+BC sinA
sinB3
∴△ABC的周长为2
sinB+3cosB+3
sinB+3=6sin(B+3
)+3π 6
故选D.