问题 解答题
(1)化简:
1
a+1
+
1
a(a+1)

(2)解不等式组:
x-3
2
+3≥x
1-3(x-1)<8-x
答案

(1)

1
a+1
+
1
a(a+1)

=

a
a(a+1)
+
1
a(a+1)

=

a+1
a(a+1)

=

1
a

(2)

x-3
2
+3≥x①
1-3(x-1)<8-x②

由①得:x≤3,

由②得:x>-2,

故不等式组的解集是-2<x≤3.

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