问题
解答题
(1)x2-2
(2)x2-2x-2=0(配方法) |
答案
(1)x2-2
x+2=0(公式法),2
∵a=1,b=-2
,c=2,2
∴x=
=-b± b2-4ac 2a
=2
±2 8-8 2
;2
∴x1=x2=
.2
(2)x2-2x-2=0,
x2-2x=2,
x2-2x+1=2+1,
(x-1)2=3,
x-1=±
,3
x1=
+1,x2=1-3
.3
(1)x2-2
(2)x2-2x-2=0(配方法) |
(1)x2-2
x+2=0(公式法),2
∵a=1,b=-2
,c=2,2
∴x=
=-b± b2-4ac 2a
=2
±2 8-8 2
;2
∴x1=x2=
.2
(2)x2-2x-2=0,
x2-2x=2,
x2-2x+1=2+1,
(x-1)2=3,
x-1=±
,3
x1=
+1,x2=1-3
.3