问题 解答题
(1)已知x+y=12,xy=9,且x>y,求
x
1
2
-y
1
2
x
1
2
+y
1
2
的值.
(2)lg25+
2
3
lg8+lg5•lg20+(lg2)2
答案

(1)∵x+y=12,xy=9,且x>y,

x
1
2
-y
1
2
x
1
2
+y
1
2
>0

且(

x
1
2
-y
1
2
x
1
2
+y
1
2
2=
x+y-2(xy)
1
2
x+y+2(xy)
1
2
=
12-6
12+6
=
1
3

x
1
2
-y
1
2
x
1
2
+y
1
2
=
3
3

(2)lg25+

2
3
lg8+lg5•lg20+(lg2)2

=lg25+lg4+lg5•lg20+(lg2)2

=2+(1-lg2)•(1+lg2)+(lg2)2

=2+1

=3

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