问题
选择题
函数y=
|
答案
∵f(x)的定义域为:[-3,2]
令z=-x2-x+6,则原函数可以写为y=
,z
∵y=
为增函数z
∴原函数的增区间即是函数z=6-x-x2在[-3,2]上的增区间.
∴x∈[-3,-
]1 2
故选C.
函数y=
|
∵f(x)的定义域为:[-3,2]
令z=-x2-x+6,则原函数可以写为y=
,z
∵y=
为增函数z
∴原函数的增区间即是函数z=6-x-x2在[-3,2]上的增区间.
∴x∈[-3,-
]1 2
故选C.
请根据语境,将所给单词填入下列各句。 | |
| |
1. Tom likes fruit, so he likes _______ and _______. 2. —What vegetables do you like? —I like _______, _______ and _______. 3. I usually drink milk for _______ and _______. 4. —Do you like western food? —Yes, I like _______, _______ and _______. |