已知f(x)=
|
∵f(-
)=cos(-4 3
π)=-cos4 3
π=-1 3
.1 2
又∵f(
)=f(4 3
)+1=f(-1 3
)+2=cos(-2 3
π)+2=-cos2 3
π+2=-1 3
+2.1 2
∴则f(
)+f(-4 3
)的值为1.4 3
故选C.
已知f(x)=
|
∵f(-
)=cos(-4 3
π)=-cos4 3
π=-1 3
.1 2
又∵f(
)=f(4 3
)+1=f(-1 3
)+2=cos(-2 3
π)+2=-cos2 3
π+2=-1 3
+2.1 2
∴则f(
)+f(-4 3
)的值为1.4 3
故选C.