问题
选择题
△ABC的内角A,B,C的对边分别为a,b,c,已知 b=2,B=
|
答案
∵b=2,B=
π |
6 |
π |
4 |
∴由正弦定理
b |
sinB |
c |
sinC |
bsinC |
sinB |
2×
| ||||
|
2 |
7π |
12 |
∴sinA=sin(
π |
2 |
π |
12 |
π |
12 |
| ||||
4 |
则S△ABC=
1 |
2 |
1 |
2 |
2 |
| ||||
4 |
3 |
故选B
△ABC的内角A,B,C的对边分别为a,b,c,已知 b=2,B=
|
∵b=2,B=
π |
6 |
π |
4 |
∴由正弦定理
b |
sinB |
c |
sinC |
bsinC |
sinB |
2×
| ||||
|
2 |
7π |
12 |
∴sinA=sin(
π |
2 |
π |
12 |
π |
12 |
| ||||
4 |
则S△ABC=
1 |
2 |
1 |
2 |
2 |
| ||||
4 |
3 |
故选B