问题 填空题

一个由静止开始作匀加速运动的物体,它在头4秒内的位移是32米,则它在第5秒末的速度是______,前2秒内的平均速度是______.

答案

因为物体做初速度为0的匀加速直线运动,根据位移时间关系有:

x=

1
2
at2?a=
2x
t2
=
2×32
42
=4m/s2

则物体在第5s末的速度v5=at5=4×5m/s=20m/s

物体在第2s末的速度v2=at2=8m/s

所以物体在前2s内的平均速度

.
v
=
v0+v
2
=
0+8
2
m/s
=4m/s

故答案为:20m/s,4 m/s

阅读理解
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