问题 解答题
解下列各题:
(Ⅰ)计算:2log510+log50.4-3log52;
(Ⅱ)已知x,y∈R+,且3x=22y=6,求
1
x
+
1
2y
的值.
答案

(Ⅰ)原式=log5102+log50.4-log523

=log5(100×0.4÷8)

=log55

=1.

(Ⅱ)∵x,y∈R+,且3x=22y=6,

∴x=log36,2y=log26.

1
x
+
1
2y
=
1
log36
+
1
log26

=log63+log62

=log6(3×2)

=1.

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