问题
问答题 简答题
计算题:发电机检测时,我们发现定子侧各相线圈的直流电阻值分别为0.24欧,0.28欧,0.20欧,请计算此三相绕组的线不平衡率?
答案
参考答案:
解:Rab=0.24Rac=0.28Rbc=0.20
ΔR=(Rac-Rbc)/Rp*100%
Rp=(Rab+Rbc+Rac)/3=(0.24+0.28+0.20)/3=0.24
(0.28-0.20)/0.24*100%=33%
计算题:发电机检测时,我们发现定子侧各相线圈的直流电阻值分别为0.24欧,0.28欧,0.20欧,请计算此三相绕组的线不平衡率?
参考答案:
解:Rab=0.24Rac=0.28Rbc=0.20
ΔR=(Rac-Rbc)/Rp*100%
Rp=(Rab+Rbc+Rac)/3=(0.24+0.28+0.20)/3=0.24
(0.28-0.20)/0.24*100%=33%