用因式分解法解下列方程:
(1)(x-1)2-2(x2-1)=0;
(2)(x-1)(x+3)=12.
(1)分解因式得:(x-1)2-2(x+1)(x-1)=0,
(x-1)[(x-1)-2(x+1)]=0,
x-1=0,(x-1)-2(x+1)=0,
x1=1,x2=-3.
(2)整理得:x2+2x-15=0,
(x+5)(x-3)=0,
x+5=0,x-3=0,
x1=-5,x2=3.
用因式分解法解下列方程:
(1)(x-1)2-2(x2-1)=0;
(2)(x-1)(x+3)=12.
(1)分解因式得:(x-1)2-2(x+1)(x-1)=0,
(x-1)[(x-1)-2(x+1)]=0,
x-1=0,(x-1)-2(x+1)=0,
x1=1,x2=-3.
(2)整理得:x2+2x-15=0,
(x+5)(x-3)=0,
x+5=0,x-3=0,
x1=-5,x2=3.