问题 解答题
解方程:
(1)x2-10x+25=7               
(2)3x2+8x-3=0
(3)x2-2
2
x+2=0                  
(4)x2-8x=9
(5)
2
3
y2+
1
3
y-2=0

(6)(x-2)2=(2x+3)2
答案

(1)x2-10x+25=7,

变形为:x2-10x+25-7=0,

x2-10x+18=0,

∵a=1,b=-10,c=18,

∴x=

-b±
b2-4ac
2a
=
10±2
7
2
=5±
7

∴x1=5+

7
,x2=5-
7

(2)∵a=3,b=8,c=-3,

∴x=

-b±
b2-4ac
2a
=
-8±
64+36
6
=
-4±5
3

∴x1=-3,x2=

1
3

(3)∵a=1,b=-2

2
,c=2,

∴x=

-b±
b2-4ac
2a
=
2
2
2
=
2

∴x1=x2=

2

(4)x2-8x=9,

变形为:x2-8x-9=0,

(x-9)(x+1)=0,

则:x-9=0或x+1=0,

解得:x1=9,x2=-1;

(5)方程可变形为:2y2+y-6=0,

a=2,b=1,c=-6,

∴y=

-b±
b2-4ac
2a
=
-1±
1+24
4
=
-1±5
4

∴y1=-

3
2
,y2=1;

(6)(x-2)2=(2x+3)2

变形为:(x-2)2-(2x+3)2=0,

(x-2+2x+3)(x-2-2x-3)=0,

(3x+1)(-x-5)=0,

则:3x+1=0,-x-5=0,

解得:x1=-

1
3
,x2=-5.

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