问题
填空题
设函数f(x)满足:对任意的x∈R,恒有f(x)≥0,f(x)=
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答案
由题意,f2(x)=7-f2(x-1)
∴f2(9.9)=7-f2(8.9)=f2(7.9)=7-f2(6.9)=f2(5.9)=7-f2(4.9)=f2(3.9)=7-f2(2.9)=f2(1.9)=7-f2(0.9)=2
∵对任意的x∈R,恒有f(x)≥0
∴f(9.9)=2
故答案为:2
设函数f(x)满足:对任意的x∈R,恒有f(x)≥0,f(x)=
|
由题意,f2(x)=7-f2(x-1)
∴f2(9.9)=7-f2(8.9)=f2(7.9)=7-f2(6.9)=f2(5.9)=7-f2(4.9)=f2(3.9)=7-f2(2.9)=f2(1.9)=7-f2(0.9)=2
∵对任意的x∈R,恒有f(x)≥0
∴f(9.9)=2
故答案为:2