解方程:
(1)x(x-2)+x-2=0;
(2)2x2+1=3x;
(3)9(2x+3)2-4(x-2)2=0.
(1)x(x-2)+x-2=0,
分解因式得:(x-2)(x+1)=0,
可得x-2=0或x+1=0,
解得:x1=2,x2=-1;
(2)2x2+1=3x,
整理得:2x2-3x+1=0,
分解因式得:(2x-1)(x-1)=0,
可得2x-1=0或x-1=0,
解得:x1=
,x2=1;1 2
(3)9(2x+3)2-4(x-2)2=0,
分解因式得:[3(2x+3)+2(x-2)][3(2x+3)-2(x-2)]=0,
即(8x+5)(4x+13)=0,
可得8x+5=0或4x+13=0,
解得:x1=-
,x2=-8 5
.13 4