cos50°(tan10°-
|
cos50°(tan10°-
)3
=sin40°(
-sin10° cos10°
)3
=sin40°•sin10°-
cos10°3 cos10°
=
(sin10°cos60°-sin60°cos10°)2sin40° cos10°
=-2sin40°sin50° cos10°
=-sin80° cos10°
=-1.
故答案为:-1
cos50°(tan10°-
|
cos50°(tan10°-
)3
=sin40°(
-sin10° cos10°
)3
=sin40°•sin10°-
cos10°3 cos10°
=
(sin10°cos60°-sin60°cos10°)2sin40° cos10°
=-2sin40°sin50° cos10°
=-sin80° cos10°
=-1.
故答案为:-1