解方程:
(1)4x2-8x+1=0(用配方法)
(2)3(x-2)2=x(x-2)
(1)4x2-8x+1=0
x2-2x+
=01 4
(x-1)2=3 4
x-1=±3 2
∴x1=
,x2=2- 3 2
;2+ 3 2
(2)3(x-2)2=x(x-2)
(x-2)(2x-6)=0
x1=2,x2=3.
解方程:
(1)4x2-8x+1=0(用配方法)
(2)3(x-2)2=x(x-2)
(1)4x2-8x+1=0
x2-2x+
=01 4
(x-1)2=3 4
x-1=±3 2
∴x1=
,x2=2- 3 2
;2+ 3 2
(2)3(x-2)2=x(x-2)
(x-2)(2x-6)=0
x1=2,x2=3.