已知向量
|
∵
=(cos75°,sin75°),. a
=(cos15°,sin15°),. b
∴
-a
=(cos75°-cos15°,sin75°-sin15°)b
∴|
-a
|=b (cos75°-cos15°) 2+(sin75°-sin15°) 2
=2-2(cos75°cos15°+sin75°sin15°)
=
=12-2cos60°
故答案为:1
已知向量
|
∵
=(cos75°,sin75°),. a
=(cos15°,sin15°),. b
∴
-a
=(cos75°-cos15°,sin75°-sin15°)b
∴|
-a
|=b (cos75°-cos15°) 2+(sin75°-sin15°) 2
=2-2(cos75°cos15°+sin75°sin15°)
=
=12-2cos60°
故答案为:1