已知△ABC的内角B满足2cos2B-8cosB+5=0,又若
|
∵2cos2B-8cosB+5=0
∴4cos2B-8cosB+5=0,
∴cosB=
, 或cosB=1 2
(舍)3 2
∴sinB=3 2
又∵cosθ=
=
•a b |
|•|a
|b
=--9 3•5
,且θ∈(0,π)3 5
∴sinθ=4 5
∴sin(θ+B)=
•4 5
+(-1 2
)•3 5
=3 2
.4-3 3 10
已知△ABC的内角B满足2cos2B-8cosB+5=0,又若
|
∵2cos2B-8cosB+5=0
∴4cos2B-8cosB+5=0,
∴cosB=
, 或cosB=1 2
(舍)3 2
∴sinB=3 2
又∵cosθ=
=
•a b |
|•|a
|b
=--9 3•5
,且θ∈(0,π)3 5
∴sinθ=4 5
∴sin(θ+B)=
•4 5
+(-1 2
)•3 5
=3 2
.4-3 3 10