问题
填空题
若tanx=1,tan(x-y)=-2,则tan(2x-y)=______.
答案
因为:tan(2x-y)=tan[(x-y)+x]
=
=tan(x-y)+tanx 1-tan(x-y)tanx
=--2+1 1-(-2)×1
.1 3
故答案为:-
.1 3
若tanx=1,tan(x-y)=-2,则tan(2x-y)=______.
因为:tan(2x-y)=tan[(x-y)+x]
=
=tan(x-y)+tanx 1-tan(x-y)tanx
=--2+1 1-(-2)×1
.1 3
故答案为:-
.1 3