问题
判断题
乳石形成时,首先形成CaSO4的晶核,伴随着乳蛋白质为主的固形物沉淀而成长。
答案
参考答案:错
乳石形成时,首先形成CaSO4的晶核,伴随着乳蛋白质为主的固形物沉淀而成长。
参考答案:错
完形填空。 | ||||
You walk on the street, a man suddenly falls down on the road in front of you. It's a heart 1 ! What should you do? Students in Guangzhou Xiaoyuan Middle School would tell you: do first aid! (急救) Last week, doctors went to the school to 2 the kids about first aid. Students first had a lesson 3 CPR (心肺复苏术). Then they 4 on a model. They had to hold the model's nose closed with one hand and hold its mouth open with the other hand. Then they had to 5 into the model. 6 they did it 7 the right way, the model's chest (胸部) got bigger. Zhang zijin, a Junior 1 student, found CPR was 8 to do than he thought. "I breathed 9 into the model then I 10 saw its chest bigger," said the 13-year-old boy. Another boy, Chen Geng, said first aid was 11 . Now he often practices CPR at home. "I'm afraid I'll 12 how to do it." Li Yanping, a doctor said it was 13 to learn first aid. She said if a person got CPR within (在…之内) four minutes 14 the heart stops beating, his life might be saved. "The more people learn CPR, the more lives 15 be saved in the future." said Li. | ||||
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Ⅰ、在10℃和4×105Pa的条件下,当反应aA(g)⇌dD(g)+eE(g)建立平衡后,维持温度不变,逐步增大体系的压强,在不同压强下该反应建立平衡后,物质D的浓度见下表(在增大压强的过程中无其它副反应发生):
压强(Pa) | 4×105 | 6×105 | 1×106 | 2×106 |
D的浓度(mol/L) | 0.085 | 0.126 | 0.200 | 0.440 |
②压强从1×106 Pa 增加到2×106 Pa时,平衡向______反应方向移动.此时平衡向该方向移动的两个必要条件是______;______.
Ⅱ、在10℃和1.01×105Pa的条件下,往容积可变的密闭容器中充入a molA和b molB,当反应2A(g)+B(g)⇌D(g)+E(s)建立平衡后,气体密度不变,已知各物质的摩尔质量(单位:g•mol-1)分别为A18、B46、D42、E40,则a:b为______.
Ⅲ、已知T℃、P kPa时,往容积可变的密闭容器中充入2mol X和1mol Y,此时容积为V L.保持恒温恒压,使反应:2X(g)+Y(g)⇌2Z(g)达到平衡时,Z的体积分数为0.4.若控制温度仍为T℃,另选一容积为V L的固定不变的密闭容器,往其中充入一定量的X和Y,使反应达到平衡,这时Z的体积分数仍为0.4.则充入的X和Y的物质的量应满足的关系是:a n(Y)<n(X)<b n(Y),则a为______.