问题 单项选择题 A1/A2型题

不寐是以何为特征的一类疾病()。

A.睡眠时间不足

B.睡眠深度不足

C.入睡困难或睡而易醒

D.时寐时醒,醒后不能再寐

E.经常不能获得正常睡眠

答案

参考答案:E

解析:不寐是由于情志、饮食内伤,病后及年迈,禀赋不足,心虚胆怯等病因,引起心神失养或心神不安,从而导致经常不能获得正常睡眠为特征的一类病证。主要表现为睡眠时间、深度的不足以及不能消除疲劳、恢复体力与精力,轻者入睡困难,或寐而不酣,时寐时醒,或醒后不能再寐,重则彻夜不寐。

阅读理解

Life in the future will be different from life today. Between then and now many changes (改变)will happen. But what will the changes be?

The population (人口) is growing fast. There will be many people in the world and most of them will live longer than people live now.

Computers will be much smaller and more useful, and there will be at least (至少) one in every room. And computer studies will be one of the important subjects in schools then. People will work fewer hours than they do now and they will have more free time for sports, watching TV and travel. Traveling will be much cheaper and easier. And many more people will go to other countries for holidays.

There will be changes in our food, too. More land will be used for building new towns and houses for all the people. Then there will be less room for cows and sheep, so meat will be more expensive. Maybe no one will eat it every day. Instead they will eat more fruit and vegetables. Maybe people will be healthier. Work in the future will be different, too. Robots will do dangerous and hard work. Because of this, many people will not have enough work to do. This will be a problem.

小题1:In the future there will be _______.

A. much more fruit   B. more people     C. less vegetables

小题2:Every family will have at least a _____________ in the future.

A. robot            B. cow           C. computer

小题3:In the future people don’t have to __________________

A. work long hours   B. work fast      C. walk on foot

小题4:People may not eat _________ as much as they do today.

A. fruit             B. fish           C. meat

小题5:One big problem in the future is that ___________.

A. many people will not be able to find work

B. people have to work fast

C. all the work will be done by robots

填空题

(13分)A、B、C、D、E、F六种化合物,其中A、B、C、D、E均由短周期元素组成,焰色反应均为黄色,B、C、E均由三种元素组成。B、C的组成元素相同,且C的摩尔质量比B大80g/mol ,回答:

(1)固体化合物A为浅黄色粉末,该化合物中含有的化学键为               

A、离子键     B、极性共价键      C、非极性共价键     D、氢键

二、     下表为B与F实验的部分内容

①在含B的溶液中加入稀,产生浅黄色浑浊和使澄清石灰水变浑浊的无色有刺激性气味的气体
②20mL沸水中滴加F的饱和溶液1~2mL所得液体呈红褐色
③将实验②得到的红褐色液体加热蒸发,灼烧,最终得到红棕色固体
写出B与稀反应的离子方程式                                              

写出②中反应的化学方程式                                                        

(3)现由6种粒子(C中含有的阴离子),完成一个离子方程式,已知为还原剂,得到1mol需氧化剂的物质的量为       mol

(4)化合物D和E相互转化D E,若有D和E ·H2O的混合物13.04g,加热到完全反应后,气体产物通过浓H2SO4增重3.42g,剩余气体通过碱石灰增重2.20g,则混合物中D的质量为         g,E ·的化学式为