问题
填空题
若cosα=
|
答案
∵若cosα=
,α∈(0,1 7
)π 2
∴sinα=
=1-cos2α
=1- 1 49 4 3 7
∴cos(α+
)=cosαcosπ 3
-sinαsinπ 3
=π 3
×1 7
-1 2
×4 3 7
=-3 2 11 14
故答案为-11 14
若cosα=
|
∵若cosα=
,α∈(0,1 7
)π 2
∴sinα=
=1-cos2α
=1- 1 49 4 3 7
∴cos(α+
)=cosαcosπ 3
-sinαsinπ 3
=π 3
×1 7
-1 2
×4 3 7
=-3 2 11 14
故答案为-11 14