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问题 填空题
已知函数f(x)=
(
1
2
)x   x≥2
f(x+1)   x＜2
，则函数f（log23）的值为______．
答案

由题意可得：1＜log23＜2，

因为函数f(x)=

(
1
2
)x   x≥2
f(x+1)   x＜2
，

所以f（log23）=f（1+log23）=(

1
2
)1+log23=
1
6
．

故答案为

1
6
．

选择题

—When _______ your birthday?    

—_______December 2nd.     [ ]

A. is; It's            

B. is; It on    

C. are; They're      

D. does; On
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单项选择题

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A．Video

B．Faxmail

C．Graphic

D．Audio
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