问题
选择题
函数y=sinxcosx+
|
答案
∵y=sinxcosx+
cos2x-3 3
=
sin2x+1 2
•3
-1+cos2x 2 3
=
sin2x+1 2
cos2x-3 2 3 2
=sin(2x+
)-π 3 3 2
令2x+
=kπ+π 3
可得x=π 2
kπ+1 2 π 12
令k=0可得满足条件的对称轴为x=π 12
故选C
函数y=sinxcosx+
|
∵y=sinxcosx+
cos2x-3 3
=
sin2x+1 2
•3
-1+cos2x 2 3
=
sin2x+1 2
cos2x-3 2 3 2
=sin(2x+
)-π 3 3 2
令2x+
=kπ+π 3
可得x=π 2
kπ+1 2 π 12
令k=0可得满足条件的对称轴为x=π 12
故选C