问题
解答题
不查表求值:cos40°•cos80°+cos80°•cos160°+cos160°•cos40°.
答案
原式=
[cos120°+cos(-40°)+cos240°+cos(-80°)+cos200°+cos120°]1 2
=
(-cos60°+cos40°-cos60°+cos80°-cos20°-cos60°)1 2
=
[-1 2
+cos(60°-20°)+cos(60°+20°)-cos20°]3 2
=
[-1 2
+cos60°cos20°+sin60°sin20°+cos60°cos20°-sin60°sin20°-cos20°]3 2
=
[-1 2
+cos20°-cos20°]3 2
=-3 4