问题
解答题
(1)若|x+
(2)解不等式组:
|
答案
(1)由题意,得x+
=0,x=-2
.2
y-
=0,y=2 2
,2 2
则xy=-
×2
=-1.2 2
∴
=1.3 xy
(2)
,2x≥1-x① x+2<4x-1②
解不等式①,得x≥
.1 3
解不等式②,得x>1.
故不等式组的解集为x>1.
(1)若|x+
(2)解不等式组:
|
(1)由题意,得x+
=0,x=-2
.2
y-
=0,y=2 2
,2 2
则xy=-
×2
=-1.2 2
∴
=1.3 xy
(2)
,2x≥1-x① x+2<4x-1②
解不等式①,得x≥
.1 3
解不等式②,得x>1.
故不等式组的解集为x>1.