问题
解答题
求证:tan(x+y)+tan(x-y)=
|
答案
证明:左=
+sin(x+y) cos(x+y) sin(x-y) cos(x-y)
=sin[(x+y)+(x-y)] cos2x•cos2y-sin2x•sin2y
=sin2x cos2x-(cos2x+sin2x)sin2y
=
=右.sin2x cos2x-sin2y
求证:tan(x+y)+tan(x-y)=
|
证明:左=
+sin(x+y) cos(x+y) sin(x-y) cos(x-y)
=sin[(x+y)+(x-y)] cos2x•cos2y-sin2x•sin2y
=sin2x cos2x-(cos2x+sin2x)sin2y
=
=右.sin2x cos2x-sin2y