问题
解答题
已知cos(
|
答案
∵cos(
+α) =π 4
,α∈(π,3 5
),∴cos(3π 2
+2α)=-sin2α=2cos2(π 2
+α)-1=π 4
,∴sin2α=-7 25
.7 25
由题意可得
+α∈(π 4
,5π 4
),故sin(7π 4
+α)=-π 4
=-1-cos2(
+α)π 4
.4 5
故cos2α=sin(
+2α)=2sin(π 2
+α)cos(π 4
+α)=π 4
.-24 25
故(2sin2α-1)×(tanα+cotα)=
=-2cos2α sin2α
.48 7