问题
填空题
若函数f(x)的导函数f′(x)=x2-4x+3,则函数f(x+1)的单调减区间是 ______.
答案
∵f′(x)=x2-4x+3,
∴f(x)=
x3-2x2+3x+c1 3
∴f(x+1)=
(x+1)3 -2(x+1)2+3(x+1)+c=1 3
x3-x2 +1+c1 3
∴f′(x+1)=x2-2x
令f′(x+1)<0得到0<x<2
故答案为(0,2)
若函数f(x)的导函数f′(x)=x2-4x+3,则函数f(x+1)的单调减区间是 ______.
∵f′(x)=x2-4x+3,
∴f(x)=
x3-2x2+3x+c1 3
∴f(x+1)=
(x+1)3 -2(x+1)2+3(x+1)+c=1 3
x3-x2 +1+c1 3
∴f′(x+1)=x2-2x
令f′(x+1)<0得到0<x<2
故答案为(0,2)
选择正确的单词。 | |
2. What is Jenny doing? She is ___________ a song. 3. Steven is ___________ ping-pong. 4. Jenny is ___________ on the paper. 5. Lily is ___________ a picture. 6. What are you ___________? 7. She is ___________ her pen on her desk. |
短文改错 | ||
|