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由以下粒子结构示意图得出的结论中，错误的是（　　）

A．①、②分别与④、⑤反应均能形成与③电子层结构相同的粒子

B．上述粒子间能形成AB型、AB2型、A2B型化合物

C．上述粒子既有原子，又有阳离子，也有阴离子

D．上述粒子的元素在元素周期表中属同一周期

答案

A、由粒子①、②、④、⑤的最外层电子数可知，在反应中，粒子①易得2个电子、粒子②易得1个电子、粒子④易失去该层上的1个电子、粒子⑤易失去该层上的2个电子而形成与粒子③核外电子结构为2、8结构相同的粒子；故A正确；

B、根据在反应中，粒子①易得2个电子、粒子②易得1个电子、粒子④易失去该层上的1个电子、粒子⑤易失去该层上的2个电子，利用化合物中得失电子总数相等，粒子①与粒子⑤、粒子②与粒子④可形成AB型化合物；粒子⑤与粒子②可结合成AB2型化合物；粒子④与粒子①可结合成A2B型化合物；故B正确；

C、图示的五种粒子中质子数与核外电子数相等，都属于原子，不存在阳离子和阴离子；故C不正确；

D、图示的五种粒子中①②③三种原子属于第二周期，而④⑤则属于第三周期；五种粒子的元素在元素周期表中不属同一周期；故D不正确；

故选CD．

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