问题
选择题
若方程(x2+y2)2-5(x2+y2)-6=0,则x2+y2=( )
A.6
B.6或-1
C.-1
D.-6或1
答案
设x2+y2=A,原方程变形为A2-5A-6=0,
解得:A1=6,A2=-1,
∵x2+y2≥0,
∴A2=-1不符合题意,应舍去.
∴x2+y2=6.
故选A.
若方程(x2+y2)2-5(x2+y2)-6=0,则x2+y2=( )
A.6
B.6或-1
C.-1
D.-6或1
设x2+y2=A,原方程变形为A2-5A-6=0,
解得:A1=6,A2=-1,
∵x2+y2≥0,
∴A2=-1不符合题意,应舍去.
∴x2+y2=6.
故选A.