问题
解答题
已知cosα=-
|
答案
cosα=-
,α∈(3 5
,π)π 2
则sinα=4 5
cos(
-α)=π 4
sin2α=2sinαcosα=-2 10
cos2α=2cos2α-1=-24 25
cos(2α+7 25
)=cos2αcosπ 6
-sin2αsinπ 6
=π 6 24-7 3 50
已知cosα=-
|
cosα=-
,α∈(3 5
,π)π 2
则sinα=4 5
cos(
-α)=π 4
sin2α=2sinαcosα=-2 10
cos2α=2cos2α-1=-24 25
cos(2α+7 25
)=cos2αcosπ 6
-sin2αsinπ 6
=π 6 24-7 3 50