方程x2-3x+2=0的解是( )
A.1和2
B.-1和-2
C.1和-2
D.-1和2
x2-3x+2=0,
因式分解得:(x-1)(x-2)=0,
可得:x-1=0或x-2=0,
解得:x1=1,x2=2.
故选A
方程x2-3x+2=0的解是( )
A.1和2
B.-1和-2
C.1和-2
D.-1和2
x2-3x+2=0,
因式分解得:(x-1)(x-2)=0,
可得:x-1=0或x-2=0,
解得:x1=1,x2=2.
故选A
完形填空。 |
Dear David, |
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