若sin
|
由sin
-2cosα 2
=0得,tanα 2
=2,tanα=α 2
=-2tan α 2 1-tan2 α 2 4 3
=cos 2α
cos(2
+α)sin απ 4 cos 2α-sin2α
(cos2
cosα-sinπ 4
sinα)sin απ 4
=
=(cosα-sinα)(cosα+sinα) (cosα-sinα)sin α cosα+sinα sin α
=
=1+tanα tan α
=1- 4 3 - 4 3
.1 4
故答案为:
.1 4