问题
解答题
解方程:
(1)x2-2x=99;
(2)3(2x-1)=-(2x-1)2.
答案
(1)移项得:x2-2x-99=0,
(x-11)(x+9)=0,
x-11=0,x+9=0,
解得:x1=11,x2=-9.
(2)移项得:3(2x-1)-(2x-1)2=0,
(2x-1)[3-(2x-1)]=0,
2x-1=0,3-(2x-1)=0,
解得:x1=
,x2=-11 2
解方程:
(1)x2-2x=99;
(2)3(2x-1)=-(2x-1)2.
(1)移项得:x2-2x-99=0,
(x-11)(x+9)=0,
x-11=0,x+9=0,
解得:x1=11,x2=-9.
(2)移项得:3(2x-1)-(2x-1)2=0,
(2x-1)[3-(2x-1)]=0,
2x-1=0,3-(2x-1)=0,
解得:x1=
,x2=-11 2