问题
解答题
解方程:
(1)(3x+2)2=25;
(2)x2-7x+10=0.
答案
(1)(3x+2)2=25
3x+2=5或3x+2=-5
x1=1,x2=-
.7 3
(2)x2-7x+10=0
(x-2)(x-5)=0
x-2=0或x-5=0
x1=2,x2=5.
解方程:
(1)(3x+2)2=25;
(2)x2-7x+10=0.
(1)(3x+2)2=25
3x+2=5或3x+2=-5
x1=1,x2=-
.7 3
(2)x2-7x+10=0
(x-2)(x-5)=0
x-2=0或x-5=0
x1=2,x2=5.