问题
选择题
关于方程ax2=bx(a≠0)的解是( )
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答案
方程ax2=bx(a≠0),
移项得:ax2-bx=0,
分解因式得:x(ax-b)=0,
可得:x=0或ax-b=0,
解得:x1=0,x2=
.b a
故选C
关于方程ax2=bx(a≠0)的解是( )
|
方程ax2=bx(a≠0),
移项得:ax2-bx=0,
分解因式得:x(ax-b)=0,
可得:x=0或ax-b=0,
解得:x1=0,x2=
.b a
故选C
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