问题
解答题
解方程:
(1)(x-3)2=1;
(2)x2-2x-1=0;
(3)x(2x+1)-6(2x+1)=0.
答案
(1)(x-3)2=1
x-3=±1
x-3=1或x-3=-1
∴x1=4,x2=2.
(2)x2-2x-1=0
x2-2x+1=2
(x-1)2=2
x-1=±2
∴x1=1+
,x2=1-2
.2
(3)(2x+1)(x-6)=0
2x+1=0或x-6=0
x1=-
或x2=6.1 2