问题
选择题
要得到y=sin2x+cos2x的图象,只需将y=
|
答案
y=sin2x+cos2x=
(sin2xcos2
+cos2xsinπ 4
)=π 4
sin(2x+2
)=π 4
sin[2(x+2
)]π 8
∴只需将y=
sin2x的图象向左平移2
个单位,即可得函数y=π 8
sin[2(x+2
)],即y=sin2x+cos2x的图象π 8
故选B
要得到y=sin2x+cos2x的图象,只需将y=
|
y=sin2x+cos2x=
(sin2xcos2
+cos2xsinπ 4
)=π 4
sin(2x+2
)=π 4
sin[2(x+2
)]π 8
∴只需将y=
sin2x的图象向左平移2
个单位,即可得函数y=π 8
sin[2(x+2
)],即y=sin2x+cos2x的图象π 8
故选B