问题
解答题
方程:
(1)x(x-2)+x-2=0
(2)x2-4x+1=0.
答案
(1)x(x-2)+x-2=0
x2-x-2=0
(x-2)(x+1)=0
x=2或x=-1.
(2)x2-4x+1=0
(x-2)2=3
x=2+
或x=2-3
.3
方程:
(1)x(x-2)+x-2=0
(2)x2-4x+1=0.
(1)x(x-2)+x-2=0
x2-x-2=0
(x-2)(x+1)=0
x=2或x=-1.
(2)x2-4x+1=0
(x-2)2=3
x=2+
或x=2-3
.3