要使函数f（x）=

x+1

+(x-1)0+

1

2-x

有意义

则

x+1≥0 x-1≠0 2-x≠0

解得x≥-1且x≠1且x≠2

∴函数f（x）=

x+1

+(x-1)0+

1

2-x

的定义域为{x|x≥-1且x≠1且x≠2}

故答案为：{x|x≥-1且x≠1且x≠2}