问题
选择题
一元二次方程x2+3x-1=0,通过配方后变形正确的是( )
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答案
移项得x2+3x=1,
方程两边都加上(
)2得x2+3x+(3 2
)2=1+(3 2
)2,3 2
所以(x+
)2=3 2
.13 4
故选B.
一元二次方程x2+3x-1=0,通过配方后变形正确的是( )
|
移项得x2+3x=1,
方程两边都加上(
)2得x2+3x+(3 2
)2=1+(3 2
)2,3 2
所以(x+
)2=3 2
.13 4
故选B.
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